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ISL5585 Datasheet

  • ISL5585

  • 3.3V Ringing SLIC Family for Voice Over Broadband (VOB)

  • 456.00KB

  • 24頁(yè)

  • INTERSIL   INTERSIL

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ISL5585
Substituting Equation 19 into Equation 17 (V
IN
=0) and
defining
鈭咺
M
= -V
2W
/Z
L
results in Equation 37 for VTX.
V
2W
Z
L
鈥?/div>
2R
P
V
TX
= ----------- -----------------------
-
-
2
Z
L
(EQ. 37)
Understanding Phase Across the ISL5585
4-Wire to 2-Wire Phase
The phase of a signal through the ISL5585 is dependent
upon whether the source is driving the signal 4-wire to 2-wire
or 2-wire to 4-wire.
Figure 6 illustrates the phase of the input signal across the
ISL5585 when the signal is applied at the -IN pin of the
ISL5585 through the R
IN
resistor. The Transmit Amplifier
(TA) inverts the signal 180 degrees at the VTX pin. The
feedback around the tip amplifier inverts the signal again on
the tip lead. The input signal will cause AC loop current to
flow through the 20
鈩?/div>
sense resistors in the direction from
V 1 to V2 and V3 to V4. This results in an inverted signal
(referenced from tip) on the VSA and thus the VFB pin. This
out of phase signal is the signal used by the feedback path
to match the line impedance of the 2-wire side.
Combining Equations 36 and 37 results in Equation 38.
V
TX
Z
L
鈥?/div>
2R
P
Z
O
(EQ. 38)
G
2-4
=
----------
=
鈥?----------------------------------------------- = 鈥?-----------------------------------------------
-
-
2
(
Z
L
+
2R
P
+
Z
O
)
E
G
2
(
Z
L
+
2R
P
+
Z
O
)
A more useful form of the equation is rewritten in terms of
V
TX
/V
2W
. A voltage divider equation is written to convert
from E
G
to V
2W
as shown in Equation 39.
錚?/div>
Z
O
+ 2
RP
錚?/div>
-
V
2W
=
錚?/div>
---------------------------------------
錚?/div>
E
G
錚?/div>
Z
L
+
Z
O
+ 2
RP
錚?/div>
(EQ. 39)
Substituting Z
L
= Z
O
+ 2
RP
and rearranging Equation 39 in
terms of E
G
results in Equation 40.
E
G
= 2V
2W
(EQ. 40)
2-Wire to 4-Wire Phase
Figure 7 Illustrates the phase of the input signal across the
ISL5585 when the signal is applied across tip and ring.
When you鈥檙e driving the 2-wire side with a source the
ISL5585 looks like a predetermined impedance
(programmed with resistor RS). The current flows through
the 20鈩?sense resistors in the direction V2 to V1 and V4 to
V3. This results in a non-inverted signal (referenced from tip)
on the VSA and thus the VFB pin. This signal is then
inverted by the TA amplifier and the signal appearing on the
VTX putput is out of phase with the signal on tip.
Substituting Equation 40 into Equation 38 results in an
equation for 2-wire to 4-wire gain that鈥檚 a function of the
synthesized input impedance of the SLIC and the protection
resistors.
V
TX
Z
O
錚?/div>
錚?/div>
-
G
2-4
=
-----------
=
鈥?/div>
錚?/div>
-------------------------------------------
錚?/div>
=
0.416
-
V
2W
錚?(
Z
L
+
2R
P
+
Z
O
)錚?/div>
(EQ. 41)
If Z
L
is set to 600鈩? Z
O
is programmed with R
S
to be
498.76鈩?(66.5k鈩?133.33), and R
P
is equal to 49.9鈩? This
results in a 2-wire to 4-wire gain of 0.416 or -7.6dB.
When the protection resistors are set to zero, the transmit
gain is -6dB.
Summary of the Phase Through the ISL5585
4-Wire to 2-Wire (V
IN
to V
2W
) is 180
擄
out of phase
4-Wire to 4-Wire (V
IN
to V
TX
) is 180
擄
out of phase
2-Wire to 4-Wire (V
2w
to V
TX
) is 180
擄
out of phase
Transhybrid Gain
The transhybrid gain is defined as the 4-wire to 4-wire gain
(G
44
).
Z
O
錚?/div>
錚?/div>
R
S
錚?錚?/div>
= 鈥?/div>
錚?/div>
---------
錚?錚?/div>
--------------------------------------
錚?/div>
-
G
44
=
G
42
脳
G
-
24
錚?/div>
R
IN
錚?錚?/div>
Z
L
+
2R
P
+
Z
O
錚?/div>
(EQ. 42)
12

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