鈥?/div>
N
CT(p)
= Number of primary turns on the Current Transformer 鈭?[Turns]
N
CT(s)
= Number of Secondary turns on the current transformer 鈭?[Turns]
V
OUT
= Nominal output voltage of the converter 鈭?[V]
L
OUT
= Inductance value of each output inductor 鈭?[H]
N
P
= Number of primary turns on the main transformer 鈭?[Turns]
N
S
= Number of secondary turns on the main transformer 鈭?[Turns]
R
SENSE
= Value of current sense resistor on secondary of current sense transformer 鈭?[Ohms]
V
EA(cl)
= Maximum Value of the E/A output voltage 鈭?[Volts]
F
S(out)
= Switching frequency of each output 鈭?[Hz]
Determine the correct value for the slope resistor, R
SLOPE
, to provide the desired amount of slope
compensation.
N
CT
+
N
CT(p)
N
CT(s)
, Current Transformer Turns Ratio
1. Transform the Secondary Inductor Downslope to the Primary
S
L(prime)
+
V
OUT
L
OUT
N
s
,
N
p
S
L(prime)
+
2.679 A
ms
2. Calculate the Transformed Slope Voltage at Sense Resistor:
VS
L(prime)
+
S
L(prime)
N
CT
R
SENSE
,
VS
L(prime)
+
2.281 V
ms
3. Calculate the R
SLOPE
value to give a compensating ramp equal to the transformed slope voltage given
above.:
M
+
1.0
Desired ratio between the compensating ramp and the output inductor downslope ramp, transformed to the
primary sense resistor
R
SLOPE
+
10
4
M
VS
L(prime)
10
*6
,
R
SLOPE
+
35.556 kW
14
www.ti.com